Answer:
Rectangle.
Round.
Arched.
Novelty.
Square.
Oval.
Octagon.
Sunburst.
Hope this is what you're looking for :)
Brainliest please
Answer: C & D
<u>Step-by-step explanation:</u>
A binomial experiment must satisfy ALL four of the following:
- A fixed number of trials
- Each trial is independent of the others
- There are only two outcomes (Success & Fail)
- The probability of each outcome remains constant from trial to trial.
A) When the spinner is spun three times, X is the sum of the numbers the spinner lands on.
→ #3 is not satisfied <em>(#4 is also not satisfied)</em>
B) When the spinner is spun multiple times ...
→ #1 is not satisfied
C) When the spinner is spun four times, X is the number of times the spinner does not land on an odd number.
→ Satisfies ALL FOUR
- A fixed number of trials = 4
- Each trial is independent of the others = each spin is separate
- There are only two outcomes = Not Odd & Odd
- The probability of each outcome remains constant from trial to trial = P(X = not odd) = 0.50 for each spin
D) When the spinner is spun five times, X is the number of times the spinner lands on 1.
→ Satisfies ALL FOUR
- A fixed number of trials = 5
- Each trial is independent of the others = each spin is separate
- There are only two outcomes = 1 & Not 1
- The probability of each outcome remains constant from trial to trial = P(X = 1) = 0.17 for each spin
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
56, because you times 7 by 2 because Greg has 2 then you times 7 by 10 because then you get the answers 14 and 70 and take them away from each other