M∠P = 12°
m∠Q = 90° [A tangent line to a circle is perpendicular to the radius drawn to the tangent point]
m∠O = 90 - 12 = 78°
Answer: x=78°
To find the acceleration of the bicycle rider, we are going to use the acceleration formula:
![a= \frac{v_{f}-v_{i}}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv_%7Bf%7D-v_%7Bi%7D%7D%7Bt%7D%20)
where
![a](https://tex.z-dn.net/?f=a)
is the acceleration
![v_{i}](https://tex.z-dn.net/?f=v_%7Bi%7D)
is the initial speed
![v_{f}](https://tex.z-dn.net/?f=v_%7Bf%7D)
is the final speed
![t](https://tex.z-dn.net/?f=t)
is the time
We know from our problem that increases his speed from 5 m/s to 15 m/s in 10 seconds, so his initial speed is 5 m/s and his final speed is 15 m/s; therefore,
![v_{i}=5](https://tex.z-dn.net/?f=v_%7Bi%7D%3D5)
,
![v_{f}=15](https://tex.z-dn.net/?f=v_%7Bf%7D%3D15)
, and
![t=10](https://tex.z-dn.net/?f=t%3D10)
. Lets replace those values in our formula:
![a= \frac{v_{f}-v_{i}}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv_%7Bf%7D-v_%7Bi%7D%7D%7Bt%7D%20)
![a= \frac{15-5}{10}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B15-5%7D%7B10%7D%20)
![a= \frac{10}{10}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B10%7D%7B10%7D%20)
We can conclude that the acceleration of the bicycle rider 1 m/s^2
The answer to your question is...
60 times more than a minute!
Answer:
1/132
Step-by-step explanation:
1/3 ÷ 44 would be solved by multiplying 1/3 and 1/44 which is 1/132