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3 years ago

6

‼️YALL I NEED HELP PLEASE HELP DUE IN 20 MINUTES ‼️

1 answer:

yanalaym [24]3 years ago

8 0

The line (in Standard Format, Ax+By=C) is 3x+6y=-17 [note: Convention is that x-coefficient is positive].
The slope of this line is (-A/B)=(-3/6)=-1/2.

All perpendicular lines have a negative reciprocal slope: 2
The equation of the perpendicular line is: 6x - 3y = D
[switch A and B and make negative; and we need point (6,3) to determine D]
6(6)-3(3)=D
36 - 9 = D
27 = D

The perpendicular line is:
6x - 3y = 27
or 2x - y - 9

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Find the exponential function P(t)=P0a^t where P(2)=5 and P(4)=10

asambeis [7]

Answer:

$P(t)=\frac{5}{2} \cdot (\sqrt{2})^t$

Step-by-step explanation:

$P(2)=5$ meants when $t=2$ , that the value for $P(t)$ is 5.

So this gives us this equation:

$5=P_0 \cdot a^2$

$P(4)=10$ meants when $t=4$ , that the value for $P(t)$ is 10.

So this gives us this equation:

$10=P_0 \cdot a^4$

So I take equation 2 and divide it be equation 1 I get:

$\frac{10}{5}=\frac{P_0 \cdot a_4}{P_0 \cdot a_2}$

Simplifying:

$2=a^2$

Since the base for an exponential function can't be negative then $a=\sqrt{2}$ .

So plugging into one of my equations I began with gives me an equation to solve for the initial value, $P_0$ :

$5=P_0 \cdot (\sqrt{2})^2$

$5=P_0 \cdot 2$

Divide both sides by 2:

$\frac{5}{2}=P_0$

The function is:

$P(t)=\frac{5}{2} \cdot (\sqrt{2})^t$

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4 years ago

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Which operations? like adding/subtracting & multiplying/dividing?

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4 years ago

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marishachu [46]

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3 years ago

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The coordinates of the vertices of quadrilateral ABCD are (0,-4) (-4,3) (3,4) (6,-1)

aleksklad [387]

Based on the given coordinates of the quadrilateral ABCD, the slopes of the lines given at:

Slope of AB = -7/4
Slope of BC = 1/7
Slope of CD = -5/3
Slope of AD = 1/2

<h3>What are the slopes of the line?</h3>

The slope of AB is:

= (3 - (-4)) / (-4 - 0)

= -7/4

The slope of BC:

= (4 - 3) / (3 - (-4))

= 1/7

The slope of CD:

= (-1 - 4) / (6 - 3)

= -5/3

The slope of AD:

= (-1 - (-4)) / (6 - 0)

= 1/2

The rest of the question is:

The slope of AB ¯ ¯ ¯ ¯ ¯ is , the slope of BC ¯ ¯ ¯ ¯ ¯ is , the slope of CD ¯ ¯ ¯ ¯ ¯ is , and the slope of AD ¯ ¯ ¯ ¯ ¯.

Find out more on the slope of line at brainly.com/question/3493733.

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