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3 years ago

Your bill at a restaurant comes to $24.50. Your gratuity is 20%. What is the final bill?

1 answer:

Elena-2011 [213]3 years ago

4 0

The final bill will come to $29.40.

To get this answer, you must multiply 24.50 by 20% to get 4.90. Then, you add the two decimals to get the final bill price of $29.40.

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What is the value of q?

malfutka [58]

Triangles QST and RST are similar. Therefore, the following is true:

q s
--- = ---- This results in 10q=rs.
r 10

Also, since RST is a right triangle, 4^2 + s^2 = q^2.
Since QST is also a right triangle, s^2 + 10^2 = r^2.
4 s
Also: ---- = ----- which leads to s^2 = 40
s 10

Because of this, 4^2 + s^2 = q^2 becomes 16 + 40 = 56 = q^2

Then q = sqrt(56) = sqrt(4)*sqrt(14) = 2*sqrt(14) (answer)

5 0

3 years ago

Read 2 more answers

The coffee cup can hold 7/9 of a pint of liquid. If Emily pours 2/3 of a pint of coffee into a cup, how much more milk can she a

Orlov [11]

1/9 pints of milk can be added by a customer

Step-by-step explanation:

We have to subtract simple fractions to find the amount of milk that can be added to a cup of coffee

Given

Total Capacity of a cup = 7/9 pints

Coffee to be added in a cup = 2/3 pints

So in order to find the amount of milk that can be added we have to subtract the amount of coffee from the total capacity of cup.

So,

Hence,

1/9 pints of milk can be added by a customer

Keywords: Fractions, addition

7 0

2 years ago

Read 2 more answers

I need to find the Missing angle of this equilateral triangle

Marysya12 [62]

Answer:

X...................

5 0

3 years ago

Read 2 more answers

The London theater offers child tickets at 10$each and adult tickets at 20$ each.Mrs burham buys 34 tickets at a total cost of 5

kirill115 [55]

Answer:

A+C=34

10C+20A=570

4 0

3 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago