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Volgvan
3 years ago
14

The rate at which a plant grows is constant. At the 3rd week it is 12 inches tall and at the 5th week it is 20 inches tall. If t

his
information is plotted on a coordinate plane, what is the y-coordinate of the the point (1. y)?

A - 1

B- 2

C- 4

D- 9
Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

4

Step-by-step explanation:

3 (week), 12 (inches)

(3,12) = (1,4)

(x,y)

x=1

y=4

Ans- y=4

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Which number line model represents the sum of 1.25 + (-0.75) ?
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2 years ago
"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
Contact [7]
A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \  x\\5^2+10^2 \ \textgreater \  x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x^2 \ \textless \  125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \  15\\ x \ \textless \  \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \  10\\ 5^2+x^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x^2 \ \textgreater \  75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \  5\\ x \ \textgreater \  \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}

3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \  10\\ x^2+5^2 \ \textgreater \  10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}
8 0
3 years ago
Read 2 more answers
Find y.<br> Round to the nearest tenth:<br> 290<br> 500 ft<br> y<br> X<br> y = [ ? ]ft
hjlf

Answer:

  • y = 242.4
  • x = 437.3

First find the inner angle:

  • 90° - 29°
  • 61°

[ given hypotenuse = 500 ft ]

using sine rule:

\sf sin(x)= \dfrac{opposite}{hypotensue}

\hookrightarrow \sf sin(61)= \dfrac{x}{500}

\hookrightarrow \sf x=sin(61)*500

\hookrightarrow \sf x=437.3

using pythagoras theorem:

  • a² + b² = c²
  • y² + (437.3)² = 500²
  • y = √58760.1
  • y = 242.4
8 0
2 years ago
Read 2 more answers
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