extraneous root is a solution o an equation that seems to be right but when we check it (by substituting it into the original equation) it turns out not to be right
Answer:
5(a+4)
Step-by-step explanation:
expression is equivalent to 5a+20
To get the equivalent expression we need to factor the given expression
5a+ 20
5a can be written as 5 * a
20 can be written as 5*2*2
WE can see that common factor is 5 for both 5a and 20
So GCF is 5
Now we factor out GCF 5
WE put 5 outside and write all the left of factors inside the parenthesis
5a +20
5 (a+2*2)
5(a+4)
Answer:
the expression would be 20h+25
Step-by-step explanation:
Answer:
x = 0 or x = 1/2 and x = -1 for the second equation
Step-by-step explanation:
Solve for x:
4 x^2 - 2 x = 0
Factor x and constant terms from the left hand side:
2 x (2 x - 1) = 0
Divide both sides by 2:
x (2 x - 1) = 0
Split into two equations:
x = 0 or 2 x - 1 = 0
Add 1 to both sides:
x = 0 or 2 x = 1
Divide both sides by 2:
Answer: x = 0 or x = 1/2
_______________________________
Solve for x:
x^2 + 2 x + 1 = 0
Write the left hand side as a square:
(x + 1)^2 = 0
Take the square root of both sides:
x + 1 = 0
Subtract 1 from both sides:
Answer: x = -1
