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Kruka [31]
3 years ago
13

A line passes through (1, 8) and is perpendicular to the graph of y = 2x+1. What equation

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

y = -1/2x + 17/2

Explanation:

y = 2x + 1 is in slope intercept form

in the equation y = mx+b, m is the slope, and in the equation m =2

the slope of a perpendicular line is the negative reciprocal of the other slope.

slope of perpendicular= -1/m = -1/2

y = -1/2x + b

now find b by substituting in (1,8) into the partial equation

8 = -1/2 + b

b = 8+ 1/2

b = 17/2

please give thanks :) hope this helps

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Next, you will make a scatterplot. Name a point that will be on your scatterplot and describe what it represents.
klio [65]

The point (12, 190) means that the temperature after 12 hours is 190 degrees Celsius

<h3>How to make a scatter plot?</h3>

To do this, we make use of the following points

(12, 190), (14, 201), (15, 301), (16, 305), (18, 350), (20, 40), (25, 450)

Where x represents the number of hours and y represents temperature

See attachment for the scatter plot.

<h3>The description of a point</h3>

To do this, we make use of the point (12, 190)

This means that the temperature after 12 hours is 190 degrees Celsius

Read more about scatter plots at:

brainly.com/question/13984412

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8 0
2 years ago
If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
A rectangular stirp of asphalt paving is 5 meters longer than it is wide. its area is 300 square meters. find the length and wid
kow [346]
Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write
A=L\cdot W=300
Moreover, we know that the length is 5 meters longer than the width:
L=W+5
We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get
(W+5)\cdot W=300
W^2+5W-300=0
which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:
L=W+5=15+5=20
<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
7 0
3 years ago
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Sean is stacking cans of beans of the market. His shelf is 10 inches tall, 10 inches deep, and 50 inches wide. The cans are 3 in
N76 [4]

Basically you get the volume first:

10 times 10 times 50

Which is 5,000

And we're given the cans volume already:

9.42

So what we do now is divided the area by the cans for our answer:

5,000/9.42

Which is 530.785563

So Sean can stack 530 cans of beans in his shelf.

(when rounding is is 531 cans)

6 0
3 years ago
A foam toy is 2 inches wide. It doubles in size for every minute it is in water. Write an expression for the width of the toy af
alexgriva [62]

So it should be y = 2*2^x
Where x is the time and y is the final width after x minutes

6 0
3 years ago
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