A watermelon seed is 0.4 long. How far would a line of 112 watermelon seeds stretch?
1 answer:
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Answer:
0xFEE₁₆ = 7756₈
Step-by-step explanation:
Convert the hexadecimal number to decimal first
0xFEE
E = 14
F = 15
Then convert them to binary
Remainder = 0
Remainder = 1
Quotient = 1
Remainder = 1
Remainder = 1
Remainder = 1
Quotient = 1
Remainder = 1
0 F E E
0000 1111 1110 1110
Take groups of three
and multiply with where n is the place of the digit
111 111 101 110
4,2,1 4,2,1 4,2,1 4,2,1
4+2+1 4+2+1 4+0+1 4+2+0
7756
So, 0xFEE₁₆ = 7756₈
Step 1. Solve both inequalities for 
:
Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines
and 
:
(1)
(2)
Replace (1) in (2):
Solve for
:
(3)
Replace (3) in (1):
We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.
Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines
Replace (1) in (2):
Solve for
Replace (3) in (1):
We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.