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Stella [2.4K]
3 years ago
5

Which of the following would cause an increase in heat? freezing compression stirring friction

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer: Your answer would be friction.

Step-by-step explanation:

Friction produces heat because it causes the molecules on rubbing surfaces to move faster and develop more energy.

Hope this helps!

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Of the following situations, which one involves combining opposite quantities to make zero?
LenaWriter [7]

Answer:

d

Step-by-step explanation:

if Emma makes 12 cupcakes and her friends eat them all, she now has 0 cupcakes.

7 0
3 years ago
the owner of an aquatic store used 17 1/2 gallons of water to fill aquariums. he puts 5 5/6 gallons of water in each aquarium. h
Lina20 [59]

He fills 3 tanks. Hope this helps!

5 0
4 years ago
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Consider all 5 letter "words" made from the full English alphabet. (a) How many of these words are there total? (b) How many of
VARVARA [1.3K]

Answer:

a) There are 11,881,336 of these words in total.

b) There are 7,893,600 of these words with no repeated letters.

c) 896,376 of these words start with an a or end with a z or both

Step-by-step explanation:

Our words have the following format:

L1 - L2 - L3 - L4 - L5

In which L1 is the first letter, L2 the second letter, etc...

There are 26 letters in the English alphabet.

(a) How many of these words are there total?

Each of L1, L2, L3, L4 and L5 have 26 possible options.

So there are 26^{5} = 11,881,336 of these words total

(b) How many of these words contain no repeated letters?

The first letter can be any of them, so L1 = 26.

At the second letter, the first one cannot be repeated, so L2 = L1 - 1 = 25.

At the third letter, nor the first nor the second one can be repeated, so L3 = L1 - 2 = 24

This logic applies until L5

So we have

26-25-24-23-22

In total there are

26*25*24*23*22 = 7,893,600

of these words with no repeated letters.

(c) How many of these words start with an a or end with a z or both (repeated letters are allowed)?

T = T_{1} + T_{2} + T_{3}

T_{1} is the number of words that start with an a and do not end with z. So we have

1 - 26 - 26 - 26 - 25

The first letter can only be a, and the last one cannot be z. So:

T_{1} = 26^{3}*25 = 439,400

T_{2} is the number of words that start with any letter other than a and end with z. So we have

25 - 26 - 26 - 25 - 1

The first letter can be any of them, other than a, and the last can only be z. So:

T_{2} = 26^{3}*25 = 439,400

T_{3} is the number of words that both start with a and end with z. So:

1 - 26 - 26 - 26 - 1

The first letter can only be a, and the last can only be z. The other three letters could be anything. So:

T_{3} = 26^{3} = 17,576

T = T_{1} + T_{2} + T_{3} = 2*439,400 + 17,576 = 896,376

896,376 of these words start with an a or end with a z or both

4 0
3 years ago
List the first three multiples of 13.
qwelly [4]

Three multiples of 13 are

0, 13, and 26

8 0
3 years ago
What is 20% of 52 (show work)
lesya692 [45]
20% of 52

Set up a proportion.

20/100 = 52/1

Divide

52*0.2 = 10.40

Final answer: 10.4
4 0
4 years ago
Read 2 more answers
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