<span>the answer is c. energy</span>
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<h3>
What are Isomers ?</h3>
Isomers are compounds which have same empirical formula , same number of atoms are present but they have difference in arrangement if the atoms.
It is given that
There are four cis, trans isomers for 2-isopropyl-5-methylcyclohexanol
the cis, trans designations of the substituents are made relative to the oh group
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Answer:
The answer to your question is below
Explanation:
Trial 1 Trial 2
mass of Mg 0.255 g 0.353 g
mass of MgO 0.418 g 0.576 g
Chemical reaction
2Mg(s) + O₂(g) ⇒ 2MgO(s)
Question 1.
Atomic mass of Mg = 24.31 x 2 = 48.62 g
Molecular mass of MgO = 2(24.31 + 16) = 80.62 g
Trial 1
48.62 g of Mg ----------------- 80.62 g of MgO
0.255 g ---------------- x
x = (0.255 x 80.62)/48.62
x = 0.422 g of MgO
Trial 2 48.62 g of Mg ----------------- 80.62 g of MgO
0.353 g ---------------- x
x = (0.353 x 80.62)/48.62
x = 0.585 g of MgO
Question 2
Trial 1
Percent yield = 0.418/0.422 x 100 = 99%
Trial 2
Percent yield = 0.576/0.585 x 100 = 98.5%
Question 3
Average = (99 + 98.5)/2
= 98.75%
Answer :=11
Thank me later
Answer:
The correct answer is option 'E': None of the above.
Explanation:
Given that pH of the solution is 4.1537
From the basic relation of acids and bases we know that

From the definition of pOH we have
![pOH=-log[OH^{-}]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E%7B-%7D%5D)
where
[OH] is the concentration of hydroxide ions in moles/Liter (M)
Applying values and subsequently solving we get
![9.8463=-log[OH^{-}]\\\\\therefore [OH^{-}]=antilog(-9.8463)\\\\\therefore [OH^{-}]=10^{-9.8463}M](https://tex.z-dn.net/?f=9.8463%3D-log%5BOH%5E%7B-%7D%5D%5C%5C%5C%5C%5Ctherefore%20%5BOH%5E%7B-%7D%5D%3Dantilog%28-9.8463%29%5C%5C%5C%5C%5Ctherefore%20%5BOH%5E%7B-%7D%5D%3D10%5E%7B-9.8463%7DM)
![\therefore [OH^{-}]=14.246\times 10^{-11}}M](https://tex.z-dn.net/?f=%5Ctherefore%20%5BOH%5E%7B-%7D%5D%3D14.246%5Ctimes%2010%5E%7B-11%7D%7DM)