Answer:
True
Explanation:
The arrangement of three groups COOH, CO, OH in the order of reducing boiling point is as follow -
COOH > OH > CO
COOH gets strongly polarised due to the presence of electron withdrawing carboxy group and hence have strong H+ bonds as compared to that of alcohol.
Hence the given statement is true.
Answer:
The sum of first 30 terms of the arithmetic progression is <u>2160.</u>
Explanation:
For an arithmetic progression, the sum of first 
terms with first term as 
and common difference 
is given as:
Now, it is given that:
Now, plug in these values and frame two equations in 
Now, we solve equations (1) and (2) for . Subtract equation (1) from equation (2). This gives,
Now, plug in the value of 
in equation (1) and solve for .
Plug in the values of 
in the sum formula to find the sum of first 30 terms.
Now, the sum of first 30 terms is given as:
Therefore, the sum of first 30 terms of the arithmetic progression is 2160.
There isn t a 'middle' carbon because there is an even number of them
If the methyl group braches off the 3rd carbon the name is
hexa-3-methyl-3-ene
I would definitely say that's false.
hope this helps you!:-)
Answer:
see below
Explanation:
1. Predicting products (double replacement): ab + cd ---> ad + cb
KNO₃(aq) + Fe(OH)₃(s)
2. balance the equation
3KOH (aq) + Fe(NO3)₃ (aq) ---> 3KNO₃(aq) + Fe(OH)₃(s)
3. I don't know if you need this but ionic equation: only aqueous things get split into ions; gas, liquid, and solids stay together
3K⁺(aq) + 3(OH)⁻(aq) + Fe³⁺(aq) + 3NO₃⁻(aq) ---> 3K ⁺(aq) + 3NO₃⁻(aq) + Fe(OH)₃(s)
removing things on both product and reactant side
3(OH)⁻(aq) + Fe³⁺(aq) --->Fe(OH)₃(s)
