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Andreyy89
3 years ago
5

Erin wants to know if warming up will help runners sprint faster. Twenty-six track and field athletes volunteered to participate

in her study. She randomly assigns 13 athletes to warm-up for 10 minutes. All 26 participants sprint the same distance. She calculates the mean for each group and determines that the mean for the warm-up group was 10.9 seconds, and the mean for the other group was 12.9 seconds. To test the difference of means she re-randomized the data 54 times, and the differences are plotted in the dot plot below. What can Erin conclude from her study? (6 points) A dot plot is shown labeled from negative 2.5 to positive 2. Above the negative 2.5 are 3 dots. Above the negative 2 are 6 dots. Above the negative 1.5 are 9 dots. Above the negative 1 are 12 dots. Above the negative 0.5 are 6 dots. Above the 0.0 are The difference in the means is not significant because a difference of 2 is not very likely. The difference in the means is not significant because a difference of 2 is very likely. The difference in the means is significant because a difference of 2 is very likely. The difference in the means is significant because a difference of 2 is not very likely.
Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

hope it Helps

Step-by-step explanation:

Brainliest please

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Stefan purchases materials to make dog collars. Stefan purchases 10 buckles in a pack and 12 straps in a pack. Stefan doesn't wa
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No

Step-by-step explanation:

Assuming it take 1 buckle and 1 strap per collar, that means we just need to find the lowest common multiple of these 10-pack buckles and 12-pack straps.

For 10: 0, 10, 20, 30, 40, 50, "60", 70, 80, 90, 100...

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From this, it is obvious that 60 is the lowest common multiple of these two numbers. Therefore, we know that Stefan can make dog collars without having leftover supplies by using 6 10-pack buckles and 5 12-pack straps.

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3 years ago
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3 years ago
Read 2 more answers
. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS
trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = \frac{1}{2}  (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

\sqrt{17^{2}-15^{2}} = RP

RP=\sqrt{289-225}

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = \frac{1}{2} (30) (33) = 495 meter²

6 0
3 years ago
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