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3 years ago

If m ∠1 = 110°, What is m∠4 PLS HELP ASAP

Mathematics

1 answer:

ivanzaharov [21]3 years ago

3 0

Answer:

$\displaystyle 70°$

Step-by-step explanation:

Consecutive Exteriour Angles form a linear pair, so you set them equal to $\displaystyle 180°:$

$\displaystyle 180° = 110° + m∠4; 70° = m∠4$

I am joyous to assist you at any time.

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Find out the wrong number in the sequence. 623, 251, 543, 356

Jet001 [13]

I think the wrong number is 623.

Solution:
623 => 6 + 2 + 3 = 11
251 => 2 + 5 + 1 = 8
543 => 5 + 4 + 3 = 12
356 => 3 + 5 + 6 = 14.

Except 11 all other numbers are even.So, 623 is the wrong number.

4 0

4 years ago

Can you help me with number 6? Confused abit Please

Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.

To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.

First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is

$\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}$

Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is

$\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}$

Third question:

To get exactly one six, it can either be the first, second or third roll.

In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.

In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus

$\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}$

And since there are three of these combinations, The answer is

$3\frac{5^2}{6^3}$

Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is

$1 - \frac{5^3}{6^3}$

4 0

3 years ago

Find the product 5.39 divided by 0.31. (please show your work and how you got the answer)

n200080 [17]

Answer:

$\frac{5.39}{0.31} X100= \frac{539}{31}$ ≈ $17.388$ (expand this equation by multiplying both numerator and denominator by 100

Step-by-step explanation:

7 0

2 years ago

Which of the following is a monomial? c^2 c 6 c^2 − 16 −8c c^3 4c^2 − 12c 7

Lena [83]

A monomial is an expression with one term. -8c is a monomial.

4 0

3 years ago

Find the roots of the polynomial equation. 2x3 + 2x2 – 19x + 20 = 0

d1i1m1o1n [39]

First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.

Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.

So x+4 divides 2x^3+2x^2-19x+20.
(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).

If we factor out a two, we can use the quadratic formula.

2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0

then x=-4, (3+i)/2, or (3-i)/2
we have two imaginary number.
I hope it helped you

5 0

3 years ago

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