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2 years ago

Pls i gat no idea :/

Mathematics

1 answer:

barxatty [35]2 years ago

6 0

Answer:

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where r is the radius of the circle and (h,k) is the coordinates of the center of the circle. We can see that the radius is 3 units and we are given the location of the center as (-3,1) so

(x+3)^2+(y-1)^2=9

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HEEELP ASAP PLEASEEEEEEEE Find the slope of the curve f(x) = 2x^2. 2x x 4x

mrs_skeptik [129]

Answer:

Step-by-step explanation:

2 $x^{2}$

The derivative of a $x^{n}$ is na $x^{n-1}$

2 × 2 $x^{2-1}$

Multiply 2 times 2.

4 $x^{2-1}$

Subtract 1 from 2.

4 $x^{1}$

For any term t, $t^{1}$ = t

4 $x$

6 0

3 years ago

26. $4.90 is what percent greater than $4.20? 27. What amount is 621% smaller than $88?

tatiyna

Answer:

do you need the answer?

Step-by-step explanation:

6 0

4 years ago

A candle shop sells scented candles for $16 each and unscented candles for $10 each. The shop sells 28 candles today and makes $

Rudiy27

<h3>The system of linear equations that represents the situation is:</h3>

a + b = 28

16a + 10b = 400

<h3>20 scented candles and 8 unscented candles were sold</h3>

Solution:

Let "a" be the number of scented candles sold

Let "b" be the number of unscented candles sold

From given,

Cost of 1 scented candles = $ 16

Cost of 1 unscented candles = $ 10

The shop sells 28 candles today

Therefore,

a + b = 28

b = 28 - a ------- eqn 1

The shop sells 28 candles today and makes $400

Therefore,

number of scented candles sold x Cost of 1 scented candle + number of unscented candles sold x Cost of 1 unscented candles = 400

$a \times 16 + b \times 10 = 400$

16a + 10b = 400 ------ eqn 2

Substitute eqn 1 in eqn 2

16a + 10(28 - a) = 400

16a + 280 - 10a = 400

6a = 400 - 280

6a = 120

a = 20

Substitute a = 20 in eqn 1

b = 28 - 20

b = 8

Thus 20 scented candles and 8 unscented candles were sold

7 0

3 years ago

Assume that the breaking system of a train consists of two components connected in series with both of them following Weibull di

tekilochka [14]

Answer:

0.9984

Step-by-step explanation:

we have shape parameter for the first component as 2.1

characteristics life = 100000

for this component

we have

exp(-2000/100000)².¹

= e^-0.0002705

= 0.9997

for the second component

shape parameter = 1.8

characteristic life = 80000

= exp(-2000/80000)¹.⁸

= e^-0.001307

= 0.9987

the reliability oif the system after 2000 events

= 0.9987 * 0.9997

= 0.9984

7 0

3 years ago

Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and

tia_tia [17]

$p=501\cdot503\cdot\cdots\cdot597$

$q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601$

So we have $q=359,999p$ . Then

$\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q$

and the answer is D.

4 0

3 years ago