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2 years ago

Pls i gat no idea :/

Mathematics

1 answer:

barxatty [35]2 years ago

6 0

Answer:

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where r is the radius of the circle and (h,k) is the coordinates of the center of the circle. We can see that the radius is 3 units and we are given the location of the center as (-3,1) so

(x+3)^2+(y-1)^2=9

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2/3 is greater then 1/2 why?

irakobra [83]

Answer:

see below

Step-by-step explanation:

Lets get a common denominator

2/3 *2/2 = 4/6

1/2 * 3/3 = 3/6

4/6 > 3/6

2/3 > 1/2

7 0

3 years ago

Read 2 more answers

A survey of students at a university shows that 4 out of 5 drink coffee. Of the students who drink coffee, 1 out of 6 adds crea

Andru [333]

The number who drink coffee is 3/4 of 8000, so ...
... (3/4)×8000 = 6000.
Of those, 1/5 add cream, so the number of coffee drinkers who add cream to their coffee is ...
... (1/5)×6000 = 1200.
_____
Alternate solutions
We have computed ...
... (1/5)×((3/4)×8000) = 1200
Since multiplication is associative, you can multiply the fractions first, if you wish:
... ((1/5)×(3/4))×8000 = (3/20)×8000
... = 24000/20 = 1200
or
... = 3×(8000/20) = 3×400 = 1200

6 0

2 years ago

Neeeeeeeeeeeeeedddddddddddddddddddd will give brain

Igoryamba

Answer:

Step-by-step explanation:

11 times 7 =77

6 0

3 years ago

Consider two people being randomly selected. (For simplicity, ignore leap years.)

inna [77]

Answer:

$(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}$

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

$=\frac{12}{365} X\frac{12}{365} = \frac{144}{133225}$

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on same day of same month) = 1

P(2 people selected not having birthday on same day of same month):

$= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}$

P(2 people selected have birthday on the same day of same month) $= 1-\frac{364}{365} \\\\= \frac{1}{365}$

7 0

3 years ago

Express cos k as a fraction in simplest terms.

yan [13]

soh cah toa

that is the saying I use

we will use cah

c is cos

a is ajacent

h is hypotinuse

to find cos K we need to do

adjacent / hypotenuse

can you do that and write it in the comments

6 0

2 years ago