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2 years ago

15

xavier made 22 more baskets than Jared this basketball season. Write an expression for the number of basket xavier made this sea

son.

1 answer:

algol [13]2 years ago

8 0

Answer:

J+22=X

Step-by-step explanation:

J represents Jared and since Xavier made 22 more baskets than Jared you add 22 onto Jared's amount of baskets to figure out how many Xavier made.

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What is the value of the expression below

spayn [35]

Answer:

10

Step-by-step explanation:

For this you just have to plug 2 into a and 4 into b. You come to this expression:

3(2) + 4

This gives you 10

4 0

3 years ago

Read 2 more answers

How many 1/5s are in 9<br>

mr Goodwill [35]

Answer:

<u><em>There are 45 1/5ths in 9</em></u>

Step-by-step explanation:

1/5 = 5

5 * 9 = 45

<u><em>45</em></u>

<u><em></em></u>

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3 years ago

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Given that PQRS≅WXYZ, find the corresponding parts.

scoundrel [369]

Answer:

wz is the corresponding part

Step-by-step explanation:

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2 years ago

For tall heterozygotes with antennae, the offspring are:

Misha Larkins [42]

Recombinant frequency between T and A is 12%

<u>Explanation:</u>

<u></u>

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

<u>Given:</u>

<u />

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = $\frac{7}{100} + \frac{5}{100}$

Recombinant frequency = $\frac{12}{100}$

Recombinant frequency in percentage = $\frac{12}{100} X 100 = 12$ %

Therefore, recombinant frequency between T and A is 12%

8 0

3 years ago

Two cars start moving from the same point. One travels south at 24 mi/h and the other travels west at 18 mi/h. At what rate (in

matrenka [14]

Answer:

The rate at which the distance between the two cars is increasing is 30 mi/h

Step-by-step explanation:

Given;

speed of the first car, v₁ = 24 mi/h

speed of the second car, v₂ = 18 mi/h

Two hours later, the position of the cars is calculated as;

position of the first car, d₁ = 24 mi/h x 2 h = 48 mi

position of the second car, d₂ = 18 mi/h x 2 h = 36 mi

The displacement of the two car is calculated as;

displacement, d² = 48² + 36²

d² = 3600

d = √3600

d = 60 mi

The rate at which this displacement is changing = (60 mi) / (2h)

= 30 mi/h

4 0

2 years ago