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cricket20 [7]
3 years ago
12

What is (9x + 5) - (6x - 8)? What is (4x + 10) - (-3x + 5)?

Mathematics
2 answers:
DanielleElmas [232]3 years ago
5 0
For the first on it is 3x-3 and the second is 1x+15 Hope this helps :)
s344n2d4d5 [400]3 years ago
4 0
(9x+5) - (6x-8) = 9x+5 - 6x+8 = (9x-6x) + (5+8) = 3x+13

___

(4x+10) - (-3x+5) = 4x+10 + 3x-5 = (4x+3x) + (10-5) = 7x+5
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Which of the following values for x and y make the equation 4x+2y+3=19 true?
Aleksandr-060686 [28]

Answer:

x = 3, y = 2

Step-by-step explanation:

Substitute the values of x from each alternative in the previous <em>question</em>, then solve for y. This is depicted below.

  • <em>A. y = -7, x = 5, 4(5) + 2y + 3 = 19</em>
  • <em>B. y = 0 and x = 4, 4(4) + 2y + 3 = 19</em>
  • <em>C. y = 2 and x = 3, 4(3) + 2y + 3 = 1</em>
  • <em>D. y = 4, x = 2, 4(2) + 2y + 3 = 19</em>

Only the third option has a y value that is <em>comparable</em> to the value in the computations, according to the calculations.

As a result, the letter C is the correct response.

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Liono4ka [1.6K]

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3 years ago
FIRST ONE TO SOLVE IT GETS 87 PTS...<br><br> 9-3÷1/3+1=___
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it's needs 20 characters so euwbwjwuw

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Read 2 more answers
PLEASE HELP ME If 0 &lt; z ≤ 90 and sin(9z − 1) = cos(6z + 1), what is the value of z? z = 3 z = 4 z = 5 z = 6
Burka [1]

Answer:

  z = 6

Step-by-step explanation:

We know that ...

  sin(x) = cos(90 -x)

Substituting (9z-1) for x, this is ...

  sin(9z -1) = cos(90 -(9z -1))

But we also are given ...

  sin(9z -1) = cos(6z +1)

Equating the arguments of the cosine function, we have ...

  90 -(9z -1) = 6z +1

  90 = 15z . . . . . . . . . add (9z-1) to both sides

  6 = z . . . . . . . . . . . . divide by 15

_____

<em>Comment on the graph</em>

The attached graph shows 5 solutions in the domain of interest. These come from the fact that the relation we used is actually ...

  sin(x) = cos(90 +360k -x)  . . . . .  for any integer k

Then the above equation becomes ...

  90 +360k = 15z

  6 +24k = z . . . . . . . . . for any integer k

The sine and cosine functions also enjoy the relation ...

  sin(x) = cos(x -90)

  sin(9z -1) = cos(9z -1 -90) = cos(6z +1)

  3z = 92 . . . . . equating arguments of cos( ) and adding 91-6z

  z = 30 2/3

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3 years ago
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