Answer:
The amount of Soyabean = 608.82 pounds.
The amount of Oats = 900-608.82 = 291.18 pounds.
Step-by-step explanation:
Given that the Soybean Meal has 46% CP and Oats has 12% CP.
The total amount of ration is 900 lbs of 35% CP.
Let x pounds of Soyabean has been used, so,
the amount of Oats = 900-x lbs.
The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e
35% of 900 = 46% of x + 12% of (900-x)
lbs.
So, the amount of Soyabean = 608.82 pounds.
The amount of Oats = 900-608.82 = 291.18 pounds.
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
<h2>12x - 20y = -9</h2>
Step-by-step explanation:
The standard form of an equation of a line:
We have
Convert
<em>multiply both sides by 10</em>
<em>subtract 24x from both sides</em>
<em>change the signs</em>
<em>divide both sides by 2</em>
