Answer:
(A) Angles in equilateral triangle are congruent
Step-by-step explanation:
From the figure, it can be seen that in triangle ABD, 
which means that all the sides of the triangle are congruent and by the definition of equilateral triangle, ΔABD will be an equilateral triangle.
Therefore, Using the property that Angles in equilateral triangle are congruent, we can find the value of x.
Thus, option A is correct.
Answer:
25x^2 - 60xy + 36y^2
Step-by-step explanation:
(5x - 6y) ( 5x - 6y)
Use foil to get the result when this is expanded.
F: (first term in each factor): 5x*5x = 25x^2
I: Use the last term first factor multiplied by first term second factor
- 6y * 5x = - 30xy
O:Outside. Use first term first factor and last term second factor
5x * -6y = - 30xy
L: last term in both factors -6y * - 6y = 36y^2
All them together
25x^2 - 30xy - 30xy + 36y^2
and combine
25x^2 - 60xy + 36y^2
Answer:
x < -5
Step-by-step explanation:
- 2x - 7 > x+ 8
Add 2x to each side
- 2x+2x - 7 > x+2x+ 8
-7 > 3x+8
Subtract 8 from each side
-7-8 > 3x+8-8
-15 > 3x
Divide by 3
-15/3 > 3x/3
-5 >x
x < -5
Mean is when you take all the numbers and add them together and divide by the amount of numbers there
Example: Find the mean of :3,4,6,7
So you a 3+4+6+7=20 divide that by 4(because there you added 4 numbers) and that equals 5
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
