Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14
<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9
Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
Answer:
36 units
Step-by-step explanation:
If half of one of the 6 sections is three the the other half is equivalent so I multiplied 6×6 and it gave me 36 (units).
Answer:
if i'm not mistaken it's A
Answer:
Step-by-step explanation:
The total number of students is 350 + 50 + 225 + 375 = 1000.
There are 225 students in band only, as well as 50 students in both band and choir. So there are 275 students in band out of the total of 1000, or 27.5%.
There are 350 students in choir only, as well as 50 students in both choir and band. So there are 400 students in choir, 50 of whom are also in band. So the probability is 50/400, or 12.5%.
The probabilities are not the same.
Since the probabilities are not the same, the probability of being in band is affected by whether or not the student is in choir. So the events are not independent.
Answer:
Step-by-step explanation:
There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice.
