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2 years ago

A boat traveled 27 miles. at this rate how many miles would take in 1/2 hour

Mathematics

1 answer:

Shkiper50 [21]2 years ago

8 0

Answer:

1/2 mph??? if so 54 hours to travel 27 miles

Step-by-step explanation:

You might be interested in

Does the function model exponential growth or decay? f(t)=1/4⋅4^t

yarga [219]

Answer:

This is an exponential decay

Because the base of the exponent is 1/4.4 which is less than 1

Step-by-step explanation:

What is exponential growth?

when the base of our exponential is bigger than 1, which means those numbers get bigger.

What is exponential decay?

when the base of our exponential is in between 1 and 0 and those numbers get smaller.

6 0

2 years ago

Please show your work. i’ll give brainliest!

pshichka [43]

Factor 4x2−16x+16

4x2−16x+16

=4(x−2)(x−2)

Answer:

4(x−2)(x−2)

6 0

3 years ago

Read 2 more answers

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago

Solve for x.

PSYCHO15rus [73]

The answer is the first option: 1) $x$ > the quantity $4$ times $b$ minus $9$ all over $a$

The explanation is shown below:

1. To solve this problem you must pply the following proccedure:

2. Move the term $4b$ to the left member. As the variable is negative, multiply the expression by $-1$ and change the direction of the sign:

$-ax+4b>9\\ (-1) -ax>9-b4 (-1)\\ x>\frac{ab-9}{a}$

6 0

2 years ago

Solve each equation. Check your answer<br>r/238=8

ozzi

You have to get r by itself on one side. Multiply both sides by 238 to cancel it out of the denominator on the left side.

You are left with r = 8 × 238 or r = 1904.

To check, plug 1904 back into the equation.

1904 ÷ 238 = 8
8 = 8 (True)

5 0

3 years ago