Answer:
Joe's wife must drive at a rate of 45km/hour.
Step-by-step explanation:
We are given that Joe leaves home and bikes at a speed of 30km/hour. Joe's wife leaves home five minutes later by car, and we want to determine her speed in order for her to catch up to Joe in 10 minutes.
Since Joe bikes at a speed of 30km/hour, he bikes at the equivalent rate of 0.5km/min.
Then after five minutes, when his wife leaves, Joe is 5(0.5) or 2.5 km from the house. He will still be traveling at a rate of 0.5km/min, so his distance from the house can be given by:

Where <em>t</em> represents the time in minutes after his wife left the house.
And since we want to catch up in 10 minutes, Joe's distance from the house 10 minutes after his wife left will be:

Let <em>s</em> represent the wife's speed in km/min. So, her speed times 10 minutes must total 7.5 km:

Solve for <em>s: </em>
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Thus, Joe's wife must drive at a rate of 0.75km/min, or 45km/hour.
Answer:
4
Step-by-step explanation:
4-2=2
Answer:
Option C (The expression 2.35c + 1.75m represents the money earned from selling c bags of cookies and m bags of muffins).
Step-by-step explanation:
It is given that a bag of cookies is priced at $2.35 and a bag of muffin is priced at $1.75. It is also given that the student sells c bags of cookies and m bags of muffins. The total revenue earned by the student by selling c bag of cookies = $2.35 * c bags = $2.35c and the total revenue earned by the student by selling m bag of muffins = $1.75 * m bags = $1.75m. Therefore, the total revenue earned by the student by selling both cookies and muffins = 2.35c + 1.75m. This expression (2.35c + 1.75m) represents the money earned from selling c bags of cookies and m bags of muffins. Therefore, C is the correct choice!!!
Answer: 15
Explanation: multiply 20 by .75
Answer:
A. { -20, -10, 20 }
Step-by-step explanation:
Given:
The function is given as:

Let us simplify the function.
First, we use the identity 

Next, we use the identity 

Now, the function can be rewritten as:

Now, the zeros are those values of
for which 
Now, for
, we must have either of the factors 0.


The factors
and
can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the
values.
So, the possible set of zeros are { -20, 10, 20 }.