The exterior angles of a regular pentagon has a measure of 360-108= 252 degrees
the sum of these exterior angles will be 5*252=1260 degrees
a regular nonagon (9-gon) has the exterior angles measure of 360 -140 = 220 degrees
the sum of these exterior angles of a nonagon will be equal 9*220=1980 degrees
so from these result that
the sum of the measures of the exterior angles of a regular 5-gon is less than the sum of the measures of the exterior angles of a 9-on
hope this will help you
Answer:
96
Step-by-step explanation:
3*4*8=96
Answer:
108
Step-by-step explanation:
It is in the middle of all the numbers, which makes it the median.
The most important part of this problem is reading the problem carefully and then solving it. Most of the required information's are already given in the question. Let us now focus on the problem in hand.
(12z^2 - 7z -12)/(3z^2 + 2z - 8) = [12z^2 - 16z + 9z - 12]/[3z^2 + 6z - 4z - 8]
= [4z(3z - 4) + 3(3z - 4)/[(3z(z + 2) -4(z + 2)]
= [(4z + 3)(3z - 4)]/(z + 2) (3z - 4)]
= (4z + 3)/(z + 2)
The above deduction is the simplified form. I hope that this is the answer that has come to your desired help.