Question

Oi can someone help me with this one ^{2}-12x-28=0 This is still pretty confusing for me

Answer 1

Answer:

Both answers should be -2 and 14.

Step-by-step explanation:

Using the quadratic formula:

$x^{2}-12x-28=0\\\\x=\frac{-(-12)+-\sqrt{(-12)^2-4(1)(-28)} }{2(1)}\\\\x= \frac{12+-\sqrt{144+112} }{2}\\\\x= \frac{12+-\sqrt{256} }{2}\\\\x= \frac{12+-16 }{2}\\\\x=6+-8$

Therefore:

$x_{1} =6+8=14\\x_{2}=6-8=-2$