Answer:
I think you would have to multiply 1,500 by 12 and also by 18 to figure it out.
Step-by-step explanation:
" "
/Answer:
the verry last one
Step-by-step explanation:
14). (Take π value as 22/7)
circumference = 66in
2πr = 66in
2×22/7×r = 66
r = 66×7/2×22
r = 21/2in
d = 2r => d = 2×21/2
therefore diameter of the circle = 21in
15). (Take π value as 3.14)
Circumference = 3.14m
2πr = 3.14m
2×3.14×r = 3.14
r = 3.14/3.14×2
r = 1/2m
Therefore the radius of the circle = 0.5m
16). (Take π value as 22/7)
Circumference = 33km
2πr = 33km
2×22/7×r = 33
r = 33×7/2×22
r = 21/4
d = 2r
d = 2×21/4
d = 21/2km
Therefore the diameter of the circle = 10.5km
Answer: 
Step-by-step explanation:
Given
Julien's parents want $64,000 at the end of 3 years
The rate of interest is 10% annually
Suppose they invested P amount initially
So, compound interest, compounded monthly is
![\Rightarrow A=P\left( 1+\frac{r}{n}\right)^{nt}\quad [\text{n=Numner of compounding periods}]\\\\\text{Insert the values}\\\Rightarrow 64,000=P\left( 1+\frac{0.10}{12}\right)^{12\times 3}\\\\\Rightarrow 64,000=P\left( 1+\frac{10}{12}\right)^{36}\\\\\Rightarrow P=\dfrac{64000}{1.3481}\\\\\Rightarrow P=\$\ 47,471.37\approx \$ 47,471](https://tex.z-dn.net/?f=%5CRightarrow%20A%3DP%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%5Cquad%20%5B%5Ctext%7Bn%3DNumner%20of%20compounding%20periods%7D%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5CRightarrow%2064%2C000%3DP%5Cleft%28%201%2B%5Cfrac%7B0.10%7D%7B12%7D%5Cright%29%5E%7B12%5Ctimes%203%7D%5C%5C%5C%5C%5CRightarrow%2064%2C000%3DP%5Cleft%28%201%2B%5Cfrac%7B10%7D%7B12%7D%5Cright%29%5E%7B36%7D%5C%5C%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B64000%7D%7B1.3481%7D%5C%5C%5C%5C%5CRightarrow%20P%3D%5C%24%5C%2047%2C471.37%5Capprox%20%5C%24%2047%2C471)
