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pickupchik [31]
4 years ago
12

7. Write the slope-intercept form of the equation that passes through the point (2, 3) and is perpendicular to the line y = 5/8x

- 4 y = 5/8x + 17/4 y = -5/8x + 7/4 y = -8/5x + 31/5 y = -8/5x - 31/5
Mathematics
1 answer:
Vinvika [58]4 years ago
4 0

Answer:

y = -8/5 x + 31/5

Step-by-step explanation:

Write the slope-intercept form of the equation that passes through the point (2, 3) and is perpendicular to the line y = 5/8x - 4 y = 5/8x + 17/4 y = -5/8x + 7/4 y = -8/5x + 31/5 y = -8/5x - 31/5

The slopes of perpendicular lines are negative reciprocals.

Slope of given line: 5/8

Slope of perpendicular line: -8/5

Point on perpendicular line: (2, 3)

Slope-intercept form of the equation of a line:

y = mx + b

We know the slope of the perpendicular is -8/5, so now we have

y = -8/5 x + b

We need to find b.

We use the given point for x and y and solve for b.

y = -8/5 x + b

3 = -8/5 * 2 + b

15 = -8 * 2 + 5b

15 = -16 + 5b

5b = 31

b = 31/5

Now that we know that b = 5, we can write the equation of the perpendicular line:

y = -8/5 x + 31/5

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ale4655 [162]

Answer:

See below ↓↓

Step-by-step explanation:

<u>Plan 1</u>

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<u>Plan 2</u>

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<u>Equating them</u>

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⇒ 33x = 363

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<u>Part B</u>

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3 0
3 years ago
What value of x is in the solution set of 8x - 6&gt; 12+2x​
MrRa [10]

Answer:

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Step-by-step explanation:

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6 0
4 years ago
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Cloud [144]

Answer:

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Step-by-step explanation:

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6 0
4 years ago
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You are swinging a bucket in a circle at a velocity of 7.8 ft/s. The radius of the circle you are making is 1.25 ft. The acceler
Ksju [112]

Given that,

velocity, v = 7.8 ft/s

Radius, r = 1.25 ft

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7 0
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Aliun [14]
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