The third one is the answer for this question
Answer:
Step-by-step explanation:
Hello!
Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"
X~Bi (n;ρ)
ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95
n= 390
x= 303
sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78
Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.
You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:
^ρ±
* √[(^ρ(1-^ρ))/n]
=
= 2.58
0.78±2.58* √[(0.78(1-0.78))/390]
0.0541
[0.726;0.834]
With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.
I hope it helps!
Remember that the area of a rectangle is the length of the rectangle multiplied by the width of the rectangle.
In this case, we could say (where
is the area of the rectangle):

Substituting the values the problem gave us for
and
, we can find the formula for
in terms of
, which is:

The formula for the area of the rectangle would be A(x) = 10x³ - 20x² + 65x.
Answer:
1/12
Step-by-step explanation:
1/6x
1/2
1/12
its lined up just in case
Answer:
0.44ft/hr
Step-by-step explanation:
Given parameters:
Quantity of rainfall = 8inches
1ft = 12inches
so;
= 0.67ft
Time =
hr
Unknown:
Rate of rainfall expressed in ft/hr = ?
Solution:
The rate of the rainfall is given as;
Rate =
Rate =
= 0.44ft/hr