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2 years ago

Compare and contrast positive and negative slopes

Mathematics

1 answer:

zvonat [6]2 years ago

7 0

They are both slopes. Negative slopes go down, while positive slopes go up.

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rail fares go up by 10%, and josie’s new season ticket to london costs £1342. calculate how much more she has to pay now than sh

Naya [18.7K]

Answer:

£134.2 more

Step-by-step explanation:

Divide 1342 by 100

Then you get 13.42

Times that by 10 and £134.2 is 10%

6 0

2 years ago

815 dived by 15 in quotiens

Dmitriy789 [7]

Your answer will be a repeating decimal or fraction

54.333

54 1/3

4 0

2 years ago

PLEASE HELP ME UNDERSTAND! I don’t know how to find.... ML , CD, AC, UW (one explanation is ok too)

nlexa [21]

Step-by-step explanation:

So the way you do this is if it says 'Find AC' and on the angle you see different letters connect then on the lines and name the angle

More that 90°= Obtuse

90° angle= 90° angle

Less than a 90° angle= isosolines angle

4 0

2 years ago

Geometry help please!!

Nostrana [21]

Answer: 13

Step-by-step explanation:

Equilateral triangle means that all sides are equal

Soo

3x + 1 must be equal to 5x - 9

3x + 1 = 5x - 9

-2x = -10

x = 5

Substitute x as 5 into either side value

3(5) + 1 = 15 + 1 = 16

So, all sides equal 16

Which means that y + 3 also equals 16

y + 3 = 16

y = 13

7 0

2 years ago

g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

2 years ago