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3 years ago

H(x) = √x-10 Determine for each x-value whether it is in the domain of h or not.

Mathematics

1 answer:

Lesechka [4]3 years ago

5 0

Answer:

0 is not in domain

5 is not in domain

10 is in domain

Step-by-step explanation:

10 is in domain because inputting 10 into the function gives an output of 0

0 is not in th domain because 0 gives us the square root of a negative number, and the quare of a negative number isnt a real number

5 is not in the domain for the same reason

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4 years ago

10) -6x + 8y = 0<br> -3x + 4y = 2<br><br> Infinite solution or no solution

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3 years ago

Find the area of the polygon

Oksana_A [137]

Answer:

Area of a regular polygon formulas

Step-by-step explanation:

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3 years ago

A rectangle has a perimeter of 2x^2+8x-10 the length of the rectangle is 3x-1. What is the width as an expression

4vir4ik [10]

Answer: The width is $x^{2}$ + 1x -4

Step-by-step explanation:

We know to find the perimeter we have to add the distance around the rectangle.The distance can also be sought as 2 times the length plus times the width.

So as a formula is like P = 2l + 2w where P is the perimeter.

We are given the perimeter so we can plot it into the formula and also plot in the length because it says the length is 3x -1

$2x^{2}$ +8x - 10 = 2(3x -1) + 2w Now we have to solve for w .Break it down

( $2x^{2}$ + 8x -10) = (6x -2 )+ 2w subtract 6x - 2 from both sides

( $2x^{2}$ + 8x -10) - (6x -2) = 2w

( $2x^{2}$ + 2x -8) = 2w now divide both sides by 2

$\frac{2x^{2} +2x-8 }{2} = w$ One the left side factor the numerator

$\frac{2(x^{2} +1x-4)}{2}$ = w Now multiply both sides by 2

w =( $x^{2}$ + 1x-4 )

The width is x^2 + 1x -4

4 0

4 years ago