Question

A rectangle has a perimeter of 2x^2+8x-10 the length of the rectangle is 3x-1. What is the width as an expression

Answer 1

Answer:   The width is $x^{2}$ + 1x -4

Step-by-step explanation:

We know to find the perimeter we have to add the distance around the rectangle.The distance can also be sought as 2 times the length  plus times the width.

So as a formula is like  P = 2l + 2w  where P is the perimeter.

We are given the perimeter so we can plot it into the formula and also plot in the length because it says the length is 3x -1  

$2x^{2}$+8x - 10 = 2(3x -1) + 2w    Now we have to solve for w .Break it down

($2x^{2}$ + 8x -10) = (6x -2 )+ 2w       subtract 6x - 2 from both sides  

($2x^{2}$ + 8x -10) - (6x -2) = 2w        

(  $2x^{2}$ + 2x -8) = 2w  now divide both sides by 2  

$\frac{2x^{2} +2x-8 }{2} = w$    One the left side factor the numerator  

$\frac{2(x^{2} +1x-4)}{2}$   = w   Now multiply both sides by 2  

  w =( $x^{2}$ + 1x-4 )

The width is x^2 + 1x -4