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Mathematics

2 answers:

Leno4ka [110]3 years ago

5 0

The answer is in the picture download photo math since you’re still in middle school you can still use it but you won’t be able to once you reach 11th cause the math gets too hard for the app

olganol [36]3 years ago

5 0

Answer:

x=-3

Step-by-step explanation:

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PLEASE HELP SOON. Answer any amount.

LiRa [457]

No.5=1/3x=21
So x is twenty one21

6 0

3 years ago

Given that lines a and b are parallel, what angles formed on line b when cut by the transversal are congruent with ∠2?

Kruka [31]

Answer:

The angles formed on line b when cut by the transversal are congruent with ∠2 are $\angle{6}\text{ and }\angle{7}$

Step-by-step explanation:

Consider the provided information.

If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .

The angles on the same corners are called corresponding angle.

Alternate Angles: Angles that are in opposite positions relative to a transversal intersecting two lines.

∠2 and ∠6 are corresponding angles

Therefore, ∠2 = ∠6

∠2 and ∠7 are alternate exterior angles

Therefore, ∠2 = ∠7

Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are $\angle{6}\text{ and }\angle{7}$

3 0

3 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$