The answer is D cause 1/4 of 33$ is 8.25 so you do 33+33+33 which is 99 then you multiply that by 6 which is 594 then you multiply 8.25 by 3 to account for all the workers then add that to 594 and then you get your answer which is 618.75
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
1/2 ^w : decay factor after w weeks
hope this helps
Step-by-step explanation:
Answer:
B. 81 weeks
Step-by-step explanation:
If we plug everything into the equation it should look like this:
Then we would subtract 1 from both sides, then we are left with <em>w:</em>
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<em>Hope this helps!</em>
Answer:
$11
Step-by-step explanation:
first you subtract 16 from 82 to get 66. then you divide 66 by 6( the number of sweatshirts and hoodies) and you get $11
