Ask question

Ask question

All categories

3 years ago

15

Jamie wants to put tiles on the walls and floor of his room (but not on the ceiling). The length of his room is 10 ft, the width

is 14 ft, and the height is 12 ft. If each tile is 1 ft long and 1 ft wide, how many tiles will Jamie need/

1 answer:

slava [35]3 years ago

8 0

Answer:

Jamie would need 140 tiles.

You might be interested in

Create three geometric sequences of your own (including one that is decreasing). Extend your sequences to include five terms. Th

Karo-lina-s [1.5K]

Answer:

a) $a_n=5\,\,(2)^{n-1}$

b) $b_n=100\,\,(\frac{1}{2} )^{n-1}$

c) $c_n=160\,\,(-\frac{1}{2} )^{n-1}$

Step-by-step explanation:

a) Geometric sequence with first term 5 and common ratio 2, where the nth term can be calculated via:

$a_n=5\,\,(2)^{n-1}$

The first five terms are: $a_1=5;\,\,\,a_2=10;\,\,\,a_3=20; \,\,\,a_4=40;\,\,\,a_5=80$

b) Geometric sequence with first term 100 and common ratio 1/2, where the nth term can be calculated via:

$b_n=100\,\,(\frac{1}{2} )^{n-1}$

The first five terms are: $a_1=100;\,\,\,a_2=50;\,\,\,a_3=25; \,\,\,a_4=12.5;\,\,\,a_5=6.25$

c) Geometric sequence with first term 160 and common ratio -1/2, where the nth term can be calculated via:

$c_n=160\,\,(-\frac{1}{2} )^{n-1}$

The first five terms are: $a_1=160;\,\,\,a_2=-80;\,\,\,a_3=40; \,\,\,a_4=-20;\,\,\,a_5=10$

4 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

Set <em>u</em>: $\displaystyle u = 4x^{-2}$
[<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

<u>Step 3: Integrate Pt. 2</u>

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

The quotient of a number and three, increased by one <br><br><br> Using the variable N

solniwko [45]

N÷3+1 or can be stated as 3÷n+1

5 0

3 years ago

Find the area of each composite figure. Use 3.14 for π. Round to the nearest tenth if necessary. Whats the correct label?

GuDViN [60]

Step-by-step explanation:

Square= bh

Square= 2×2=

half-circle = 1/2Pi*r×r

half-circle 2 = 1/2Pi*r×r

We would put 1/2 for the half-circle because its half of a circle. And we square it because where finding area. The middle is square, and the two up top is half a circle. Hope that helps :D

8 0

3 years ago

Read 2 more answers

This is worth 30 points

Mama L [17]

Answer:

There's 3 questions which one do I answer?

Step-by-step explanation:

6 0

3 years ago