Anyone know the answer

PJ is Decorating Pupcakes for Rocky´s Birthday Party. Her Color Scheme is Black, Purple, and Green. She Will use This Spinner to

Inga [223]

The answer to your question is C.

3 0

2 years ago

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How do you convert repeating decimals into fractions

diamong [38]

Answer:So, To convert a decimal to a fraction, begin by placing that decimal over the number 1. Then keep multiplying both the numerator (top number) and denominator (bottom number) by 10 until both are whole numbers.

Step-by-step explanation:

So, To convert a decimal to a fraction, begin by placing that decimal over the number 1. Then keep multiplying both the numerator (top number) and denominator (bottom number) by 10 until both are whole numbers.

7 0

3 years ago

AND Use el adverbio TAN o una forma del adjetivo TANTO para formar frases de comparación. (1 point each, 4 points total) Ejemplo

dybincka [34]

Answer:

10. México es un país con mucha gente (más de 130 millones de personas). Aunque es más grande, la Argentina tiene menos 45 millones de personas.

ARGENTINA NO ES TAN GRANDE COMO MÉXICO.

11. Ellos tienen cinco hijos y nosotros otros tenemos cinco hijos también.

ELLOS TIENEN TANTOS HIJOS COMO NOSOTROS.

12. Carlos no tiene mucho dinero, pero Felipe es rico.

CARLOS NO TIENE TANTO DINERO COMO FELIPE.

13. Linda es muy simpática, me gusta Dolores.

LINDA ES TAN SIMPÁTICA, PERO ME GUSTA DOLORES.

6 0

3 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$