This is the answer to the problem. You basically substitute the -6 in for the f(x)
Luke asserts that since the shape is constant, two circles are always isometric. he is wrong. No, an isometry keeps the size and shape intact.
Given that,
Luke asserts that since the shape is constant, two circles are always isometric.
We have to say is he accurate.
The answer is
No, an isometry keeps the size and shape intact.
Because a shape-preserving transformation (movement) in the plane or in space is called an isometric transformation (or isometry). The isometric transformations include translation, rotation, and combinations thereof, such as the glide, which combines a translation with a reflection.
Therefore, Luke asserts that since the shape is constant, two circles are always isometric. he is wrong. No, an isometry keeps the size and shape intact.
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Answer:
The equation is y = (2/3)x + (4/3).
Step-by-step explanation:
First, you have to change the equation into slope-intecept formula to find its gradient (slope) :
Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :
Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :
First, before multiplying to cancel the fraction, let's isolate x by subtracting both sides by 3:
b/9 < 1
To cancel out the fraction, we multiply both sides by 9:
x < 9
Answer:
area of a square is S^2
s = 5n^4
area = (5n^4)^2 = 25n^8
Step-by-step explanation:
