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3 years ago

(x-y)/(2)+(7y)/(3)=5

Mathematics

1 answer:

Alexeev081 [22]3 years ago

7 0

I hope that answers your question correct or not

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Sinx/4=1/2 find the solution

Murrr4er [49]

Sin (x/4) = 1/2
x/4 = sin⁻¹ 1/2
x/4 = 45
x = 45*4
x = 180

So, your final answer is 180

Hope this helps!

7 0

3 years ago

A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ

Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation: Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

$^{10}C_r=210.$

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

$^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10$

If r = 2, then

$^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45$

If r = 3, then

$^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120$

If r = 4, then

$^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.$

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0

3 years ago

Read 2 more answers

Suppose there are signs on the doors to two rooms. The sign on the first door reads "In this room there is a lady, and in the ot

9966 [12]

Answer:

The lady is on the second door

Step-by-step explanation:

we have that

The sign on the first door reads "In this room there is a lady, and in the other one there is a tiger"

The sign on the second door reads "In one of these rooms, there is a lady, and in one of them there is a tiger."

The sign on the second door is true

The sign on the first door is true or false

Since one of these signs is true and the other is false, the sign in the first door must be false

therefore

The lady is on the second door

5 0

3 years ago

Which set of shapes appear to be similar? (Answers in picture)

12345 [234]

Answer: D

Step-by-step explanation: The Right Shape On D Is Just Smaller Than The Left One

8 0

3 years ago

Expand (3a – 5b)(2a +36)

olga_2 [115]

Answer:

6a^2+108a-10ab-180b

Step-by-step explanation:

4 0

3 years ago