Answer:
.
Step-by-step explanation:
We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.
We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.
So there are 4 prime number in set A and total numbers are 5.
We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.
So there are 3 prime number in set B and total numbers are 4.
Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.
Therefore, the probability that both numbers are prime would be .
H= -1 here's why:
7 = 12 + 5h
First you subtract 12 from both sides then the equation would look like:
-5 = 5h
Then you would divide the equation by 5 from both sides it would then look like:
-1 = h
Answer:
45:36
Step-by-step explanation:
Please correct me if not correct.
<h3><u>The first number is equal to 10.</u></h3><h3><u>The second number is equal to 8.</u></h3>
x = 2 + y
2x = 3y - 4
Because we have a value of x, we can plug it into the second equation to solve for y.
2(2 + y) = 3y - 4
4 + 2y = 3y - 4
Subtract 2y from both sides.
4 = y - 4
Add 4 to both sides.
8 = y
We can plug this into the original equation to solve for x.
x = 2 + 8
x = 10