Answer: See explanation
Explanation:
a. The Journal entries to record the issuance of the note will be:
Debit Accounts payable $10000
Credit Notes payable $10000
(To record the issuance of note to creditor)
b. The journal entry to record thehe payment of the note at maturity, including interest will be:
Debit Notes payable $10000
Debit Interest expense $125
Credit Cash $10000 + $125 = $10125
(To record the payment on the note on maturity.
Note:
Interest expense = $10000 × 5% × 90/360
= $10000 × 0.05 × 0.25
= $125
Answer:
Explanation:
Alright so the way to do this is to use properties of integrals to make our life easier.
So we have:

So lets break this up into two different integrals that represent the same area.

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

But since we have these values we can say that:
-3 - 2 = -5
Which means that
= -5
So now we can evaluate 
Lets first break up our integrand into two integrals
= 
Now we can evaluate this:
We know that
= -5
So:
where x is evaluated at 4 to 1 so
-15 + 2(3)
So we are left with -15 + 6 = -9
Probably because it would cause chaos in the area on what to do for a solution.