Answer:
160/147
Step-by-step explanation:
Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Well each piece of the whole is what made the whole... so in that case each piece is little 1/4's of the whole....
Answer:
4.5 units
Step-by-step explanation:
In this case, if we draw the point on the xy cartesian plane, we know that the value of "x" is 4.5 and the value of "y" is 0.
Which means that when I draw this in any way, the maximum value it will take is 4.5 units, therefore the radius should not exceed this value, nor should it be less than 4.5 units since the circle would be distorted.
Which means that the radius is 4.5 units
