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Anika [276]
3 years ago
8

The inequality 2x - 3y ≥ 5 is satisfied by point (1/2,1/3 ). True False

Mathematics
2 answers:
vovangra [49]3 years ago
7 0

For this case we evaluate the following inequality in the given point and verify if it is met:

2x-3y\geq  5

(x, y) = (\frac {1} {2}, \frac {1} {3})

Substituting:

2 \frac {1} {2} -3 \frac {1} {3}\geq5

1-1\geq 5\\0\geq 5

It is not fulfilled!

The point does not satisfy the inequality

ANswer:

False

Stels [109]3 years ago
3 0

Answer:

False

Step-by-step explanation:

(1/2, 1/3) ⇒ x = 1/2 and y = 1/3

Substitute these values in the given equation;

   2x - 3y ≥ 5

  2(1/2) - 3(1/3) ≥ 5

   \frac{2}{2}  -   \frac{3}{3}

= 1 - 1 = 0

Thus the inequality is not satisfied by the given points, since 0 < 5 and ≠ 5.

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An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o
stira [4]

Answer:

H_{0}: \mu= 185 and H_{a}: \mu > 185

Step-by-step explanation:

The null hypothesis H_{0} states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form H_{0}: parameter = value

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form H_{0}: \mu= 185.

The alternative hypothesis H_{a} states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use H_{a}: \mu > 185 as his alternative hypothesis.

7 0
3 years ago
If 0.15% of budget is spent on office supplies, what decimal should you multiply budget
VMariaS [17]

Answer:

0.015

Step-by-step explanation:

0.15% = 0.0015

{transfer}

4 0
2 years ago
Need that help.......plz
Anika [276]
For Question Number one
(2+10)²+4=148

Question Number two:
(6+5)×(8-6)=22



5 0
3 years ago
How do you factor 2y^2 +13 +21
ella [17]

Answer:

2

(

y

2

+

17

)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
a test consists of 10 true false questions to pass a test a student must answer at least six questions correctly if a student gu
Delicious77 [7]

Answer:

P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)

And using the probability mass function we got:

P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205

P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117

P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439

P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098

P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977

And adding the values we got:

P(X\geq 6) = 0.377

The best answer would be:

D. 0.377

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.5)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

For this case in order to pass he needs to answer at leat 6 questions and we can rewrite this:

P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)

And using the probability mass function we got:

P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205

P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117

P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439

P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098

P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977

And adding the values we got:

P(X\geq 6) = 0.377

The best answer would be:

D. 0.377

8 0
3 years ago
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