Answer:
80
Step-by-step explanation:
why do you keep asking these questions that anyone can answer
You have to multiply all the sides
Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer:
-27 + -13 = -40
Step-by-step explanation:
Answer:
area of BMDN 8 ft²
Step-by-step explanation:
In BMDN the diagonals are BD and MN.
MN is 12/3 = 4 ft long, and BD = 4 ft.
A rhombus with equal diagonals is a square, so BMDN is a square.
In the right triangle BDN, the diagonal BD is the hypotenuse, then:
DN² + NB² = BD²
but DN = NB, then:
2*DN² = 16 ft²
DN² = 8 ft²
The area of BMDN is computed as one of its sides squared. Then, DN² is its area
