Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.
Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.
x + x + 2 = -36
2x + 2 = -36
2x = -38
x = -19
The smaller one of the two integers is -19.
x + 2 = -19 + 2 = -17
The greater of the two integers is -17.
Answer: The integers are -19 and -17.
What do you want me to do with that?
Answer:
you can use photomath or mathpapa
Answer:
-d+3.5≥4
Step-by-step explanation:
Just ask.
Hope this helps! :)
