Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
Answer:
Point (1,8)
Step-by-step explanation:
We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.
When a point divides any segment internally in the ratio m:n, the formula is:
![[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2Cy%3D%20%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
Let us substitute coordinates of point P and Q as:
,




![[x=\frac{4}{4},y=\frac{32}{4}]](https://tex.z-dn.net/?f=%5Bx%3D%5Cfrac%7B4%7D%7B4%7D%2Cy%3D%5Cfrac%7B32%7D%7B4%7D%5D)
Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Learn more about equation here
brainly.com/question/28741857
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Y=1/2x+8
I think this might be right