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uysha [10]
2 years ago
9

Arrange the steps from start to finish to factor this expression using the grouping method x^2-5x-24 drag the tiles to the corre

ct boxes not all tiles will be used step by step
Mathematics
1 answer:
rosijanka [135]2 years ago
7 0

Answer:

(x - 8)(x + 3)

Step-by-step explanation:

x² - 5x - 24

Consider the factors of - 24 which sum to give the coefficient of the x- term (- 5)

The factors are - 8 and + 3 , since

- 8 × + 3 = - 24 and - 8 + 3 = - 5

Use these factors to split the x- term

x² - 8x + 3x - 24 ( factor the first/second and third/fourth terms )

= x(x - 8) + 3(x - 8) ← factor out (x - 8) from each term

= (x - 8)(x + 3) ← in factored form

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Find the distance between (-3, 11) and (-6,4).Round to the nearest then the
Likurg_2 [28]

Answer:

d =7.6

Step-by-step explanation:

(-3,11) =(x_1,y_1)\\(-6,4)=(x_2,y_2)\\\\\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\=\sqrt{\left(-6-\left(-3\right)\right)^2+\left(4-11\right)^2}\\= \sqrt{(-6+3)^2+(4-11)^2}\\ \\d= \sqrt{(-3)^2+(-7)^2} \\\\d = \sqrt{9+49}\\ \\d = \sqrt{58}\\\\d = 7.61577\\\\d =7.6

3 0
3 years ago
Electricity usage data consists of 45 months has a mean number of units consumed is 390.47 per month with a standard deviation o
neonofarm [45]

Answer:

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0141

The margin of error is:

M = T*s = 2.0141*170.5 = 343.4

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 390.47 - 343.40 = 47.07 units per month

The upper end of the interval is the sample mean added to M. So it is 390.47 + 343.40 = 733.87 units per month

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

6 0
3 years ago
Help me fast I need please
ale4655 [162]

Answer:

2/9

Step-by-step explanation:

Since there are 18 total eggs (cracked, white, brown) we can say that the denominator will be 18.

There are 8 white eggs, and when half of those are cracked there will be 4 uncracked and 4 cracked, so 4/18.

Simplify 4/18 to 2/9 and there is your answer.

4 0
3 years ago
If point P is 4/7 of the distnace frm M to N, what ratio does the point P partiion the directed line segment from M to N
vredina [299]

Answer: 4:3.

Step-by-step explanation:

Given: Point P is \dfrac{4}{7} of the distance from M to N.

To find: The ratio in which the point P partition the directed line segment from M to N.

If Point P is between points M and N, then the ratio can be written as

\dfrac{MP}{MN}=\dfrac{MP}{MP+PN}

As per given,

\dfrac{MP}{MP+PN}=\dfrac{4}{7}\\\\\Rightarrow\ \dfrac{MP+PN}{MP}=\dfrac{7}{4}\\\\\Rightarrow\ \dfrac{MP}{MP}+\dfrac{PN}{MP}=\dfrac{7}{4}\\\\\Rightarrow\ -1+\dfrac{PN}{MP}=\dfrac{7}{4}\\\\\Rightarrow\ \dfrac{PN}{MP}=\dfrac{7}{4}-1=\dfrac{7-4}{4}=\dfrac{3}{4}\\\\\Rightarrow\ \dfrac{PN}{MP}=\dfrac{3}{4}\ \ \or\ \dfrac{MP}{PN}=\dfrac{4}{3}

Hence, P partition the directed line segment from M to N in 4:3.

7 0
3 years ago
Plz help me ASAP I'll mark brainliest
romanna [79]
Answer is:
Hope this helps

3 0
3 years ago
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