9514 1404 393
Answer:
R32.15
Step-by-step explanation:
Let x and y represent the original price of a loaf of bread and a liter of drink, respectively. The two relations given by the problem statement are ...
10x +12y = 138.90
10(1.2x) +12(1.1y) = 159.54
Multiplying the first equation by 1.2 and subtracting the second gives ...
1.2(10x +12y) -(10(1.2x) +12(1.1y)) = 1.2(138.90) -(159.54)
1.2y = 7.14 . . . . collect terms
y = 5.95 . . . . . divide by 1.2
The value of x can be found from the first equation.
10x + 12(5.95) = 138.90
10x = 67.50 . . . . . . . . . . . subtract 71.40
x = 6.75 . . . . divide by 10
Then the value of 3x+2y is ...
3(6.75) +2(5.95) = 32.15
The original price of 3 loaves and 2 liters is R31.15.
=(-24÷6)×(-2)+7
=(-3×-2)+7
=6+7
=13
I would say A or C
dont take my word for it tho idk
