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2 years ago

15

A laser printer has 300 sheets of paper and is printing at a rate of 12 pages per minute how many sheets of paper will be left i

n the printer in two and one half minutes of the printer is continuously printing

1 answer:

inysia [295]2 years ago

8 0

It has used 36 pages, so it would have 264 pages :) :) :)

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A student takes an exam containing 1818 true or false questions. If the student guesses, what is the probability that he will ge

creativ13 [48]

Probability

p=66×100/1818=3.6303630363%

After rounding to 4 decimals:

p=3.6304%

8 0

2 years ago

Read 2 more answers

How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 80% antifreeze?

Georgia [21]

Answer:

The amount of water to be added is ¹/₄ gallon

Step-by-step explanation:

Given;

amount of pure antifreeze at 100% = 1 gallon

let the amount of water to be added with 0% antifreeze = (x) gallon

then, the amount of mixture at 80% antifreeze = (x + 1) gallon

For conservation of mass, we will have the following equation;

(1 x 1) + (0)(x) = 0.8(x +1)

1 = 0.8x + 0.8

0.8x = 1 - 0.8

0.8x = 0.2

x = 0.2 / 0.8

x = ²/₈

x = ¹/₄ gallon

Therefore, the amount of water to be added is ¹/₄ gallon

8 0

3 years ago

Answer in Standard form!

myrzilka [38]

Whats the the question i can't write it in standard form if i have nothing to write

3 0

3 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Mashutka [201]

Here is the full question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

Equation:

y=-16x^2+153x+98

Answer:

10.2 seconds

Step-by-step explanation:

Given equation :

$y=-16x^2+153x+98$ shown the expression of a quadratic equation

Let y =0

∴

0 = $-16x^2+153x+98$

where;

$a=-16\\b=153\\c=98$

Using the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

replacing it with our values; we have:

$x=\frac{-153\±\sqrt{153^2-4(-16)(98)}}{2(-16)}$

$x=\frac{-153\ + \sqrt{153^2-4(-16)(98)}}{2(-16)}$ OR $x=\frac{-153\ - \sqrt{153^2-4(-16)(98)}}{2(-16)}$

$x_1=10.17$ OR $x_2=-0.60$

Hence, we go by the positive value since, is the time that the rocket will hit the ground.

x= 10.17

x = ≅ 10.2 seconds

Therefore, the rocket will hit the ground, to the nearest 100th of second. = 10.2 seconds

6 0

3 years ago

PLEASE HELP WITH THIS

Mariulka [41]

Answer:

it's the last one, 4 to the power of 5 = 1,024

Step-by-step explanation:

hope this helps!

3 0

1 year ago