Answer:
Mixture problemsare ones where two different solutions are mixed together ... should be added to the first in order to get amixture of 5% salt?4) How much ... 8 6) How many grams of pure acid must be added to 40 grams of a 20% acidsolution to ... make a Mixture that perliter?15) Solution A is 50% acid and solution B is 80% ...
Step-by-step explanation:
I) -7s^2+28st+21su
II) -8c^2+20cd
2,916 is going to be your answer, they were all multiplied by 3 hope this helps!
52x38=1976, 1976 is the answer
Answer:
x = 6
, −
6
Step-by-step explanation:
