Solution:
Let the speed of cyclist without any wind = x miles per hour
Speed of cyclist when speed of wind increases by 2 miles per hour = (x + 2 )miles per hour
Also , relation that is given between speed of cyclist without wind and with wind is :Riding with the wind at her back, a cyclist takes an hour less time to cover 80 miles than without any wind.
Converting this statement into terms of equation:
→→→To solve the Quadratic equation of type : a x² + b x + c=0, I have used discriminant method, to find the roots, which is x= ![\frac{-b\pm\sqrt{D=b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%5Cpm%5Csqrt%7BD%3Db%5E2-4ac%7D%7D%7B2a%7D)
Speed of cyclist without wind = 11.68 miles per hour
Speed of cyclist when wind is flowing = 11.68 +2 = 13.68 miles per hour
Answer:
234.93 minutes. Divide by 60 and you get 3 hours almost 4.
Step-by-step explanation:
The equation of line passing through (-8, -2) and (-4, 6) is y = 2x + 14
<u>Solution:</u>
Given that
Line is passing through point (− 8 ,− 2) and ( -4 , 6 )
Equation of line passing through point
is given by:
----- eqn 1
![\text { In our case } x_{1}=-8, y_{1}=-2, x_{2}=-4, y_{2}=6](https://tex.z-dn.net/?f=%5Ctext%20%7B%20In%20our%20case%20%7D%20x_%7B1%7D%3D-8%2C%20y_%7B1%7D%3D-2%2C%20x_%7B2%7D%3D-4%2C%20y_%7B2%7D%3D6)
Substituting given value in (1) we get
![\begin{array}{l}{y-(-2)=\frac{(6-(-2))}{(-4-(-8))}(x-(-8))} \\\\ {=>y+2=\frac{8}{4}(x+8)} \\\\ {=>y+2=2(x+8)} \\\\ {=>y+2=2 x+16} \\\\ {=>-2 x+y=14}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7By-%28-2%29%3D%5Cfrac%7B%286-%28-2%29%29%7D%7B%28-4-%28-8%29%29%7D%28x-%28-8%29%29%7D%20%5C%5C%5C%5C%20%7B%3D%3Ey%2B2%3D%5Cfrac%7B8%7D%7B4%7D%28x%2B8%29%7D%20%5C%5C%5C%5C%20%7B%3D%3Ey%2B2%3D2%28x%2B8%29%7D%20%5C%5C%5C%5C%20%7B%3D%3Ey%2B2%3D2%20x%2B16%7D%20%5C%5C%5C%5C%20%7B%3D%3E-2%20x%2By%3D14%7D%5Cend%7Barray%7D)
Thus the required equation of line is y = 2x + 14
Answer:
D. 2x2x3x3
Step-by-step explanation:
2x2 is equal to 4
4x3 is equal to 12
12x3 is equal to 36
H would equal to 4 (8+4=12)