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3 years ago

Graph y = 2/3x this khan academy buulcrap >:(

Mathematics

1 answer:

alexgriva [62]3 years ago

3 0

Answer:

.__.

Step-by-step explanation:

Start from (0,0), go up 2 units, right 3 units. Repeat and there, you graphed it! Now pat yourself on the back and move on with your life :D

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Simplify the expression below.<br> (x^4)^-6<br> ОА. x^-24<br> Ов. х^-10<br> Ос. X^10<br> OD. X^24

Montano1993 [528]

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3 years ago

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NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

Need help with both 7 and 8

Scrat [10]

You are correct with both

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3 years ago

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For which of the following conditions will the sum of integers m and n always be an odd number?

zimovet [89]

Answer:

Option K

m is an odd integer and n is an even integer

Step-by-step explanation:

The sum of intergers when one is even and another is odd results into an even number. Take for example, if x is even and the next number x+1 their sum will be 2x+1. The presence of +1 at the end shows the number is not divisible by 2 hence an odd number.

Practically, if you add 2+3=5 and 2 is even number while 3 is odd, clearly the sum being 5 is an odd number.

Otherwise, if you add two even numbers or two odd numbers the sum will be an even number.

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4 years ago

(1) Brian bought a new car. The car was on sale for

Allushta [10]

Answer:

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2) get 9.25% of $12000

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2 years ago