Answer:
<u>Option 3: 0 ≤ x ≤ ∞ </u>
Step-by-step explanation:
The domain of a function is the set of all possible x values for the function.
The given function is y = √x
The domain for the square root function should be : x ≥ 0
So, the domain = [0,∞)
Or, it can be written as inequality
So, 0 ≤ x ≤ ∞
So, the answer is option 3.
Since x=x, this is an isosceles right triangle. By the Pythagorean Theorem:
h^2=a^2+b^2 (the hypotenuse squared is equal to the sum of the squared sides)
5^2=x^2+x^2
25=2x^2
2x^2=25
x^2=25/2
x=√(25/2)
x=5/√2 now if we rationalize the denominator...
x=(5√2)/(√2√2)
x=(5√2)/2
<span>g(x) = x^2 + 4x + 3
y-intercept: let x=0. Then y=3. y-intercept is (0,3).
roots: set g(x) = 0 and solve for x. x=-1 and x=-3.
-4
axis of symmetry: find x = -b / (2a), which here is x = ----- = -2
2</span>
Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
<span>2/5 would be one...tell me if you need more.</span>
