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3 years ago

7

Which statement about these triangles is true

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

c

Step-by-step explanation:

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Help please its math I don't understand the question can you help me figure it out☺✌

pishuonlain [190]

The angle sum of a triangle is 180 degrees
So add all the angles inside and equate it to 180: 5x+2x+3x= 180
10x=180
x= 18

Because you’re finding angle L, which is 3x, and we find what the numerical value of x is
Angle L = 3x18 = 54.
Hope this helps!

8 0

4 years ago

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What does a persuasive visual designed to make an argument refer to a. visual rhetoric b. logos c. pathos

Mkey [24]

<span>a) Visual Rhetoric. Logos means creating a symbol for some fixed thing. Pathos is related to evoking pity or sadness. Both these are clearly can't be the answer. Visual Rhetoric means using visual images to communicate meaning. This includes using visual design to make an argument. So this should be the answer.</span>

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3 years ago

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The stock of Company A lost $1.18 throughout the day and ended at a value of

dmitriy555 [2]

Answer:

the percentage did the stock decline is 4%

Step-by-step explanation:

The computation of the percentage did the stock decline as follows:

= Lost value ÷ original price

= $1.18 ÷ ($1.18 + $28.32)

= $1.18 ÷ $29.50

= 4% decline

Hence, the percentage did the stock decline is 4%

7 0

3 years ago

Use cylindrical coordinates to evaluate the triple integral ∭ where E is the solid bounded by the circular paraboloid z = 9 - 16

4vir4ik [10]

Answer:

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

Step-by-step explanation:

The Cylindrical coordinates are:

x = rcosθ, y = rsinθ and z = z

From the question, on the xy-plane;

$9 -16 (x^2 + y^2) = 0 \\ \\ 16 (x^2 + y^2) = 9 \\ \\ x^2+y^2 = \dfrac{9}{16}$

$x^2+y^2 = (\dfrac{3}{4})^2$

where:

0 ≤ r ≤ $\dfrac{3}{4}$ and 0 ≤ θ ≤ 2π

∴

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} \int ^{9-16r^2}_{0} \ r \times rdzdrd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 z|^{z= 9-16r^2}_{z=0} \ \ \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 ( 9-16r^2}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} ( 9r^2-16r^4}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( \dfrac{9r^3}{3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3r^3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) d \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) \theta |^{2 \pi}_{0}$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{64}}-\dfrac{243}{320}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{160}})2 \pi$

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

4 0

3 years ago

The legal permitted speed limit for all vehicles near a school zone is

Alenkasestr [34]

C. 25 miles per hour

8 0

3 years ago

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