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svetoff [14.1K]
3 years ago
5

Frank has 5 times as many postcards as Tom. Together they have 60 postcards. Let x equal the number of postcards Tom has. Comple

te the equation that
tells you exactly how many postcards Tom has.
Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Ah

kykrilka [37]3 years ago
7 0

Answer: 12

Step-by-step explanation: 5x = 60

x = 12

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4 0
3 years ago
Jessica is deciding on her schedule for next semester. She must take each of the following classes: English 101, Spanish 102, Bi
user100 [1]
Just a random guess 22,275 tell me if it right
8 0
3 years ago
What is the GCF of 24a^3 b and 36ab^2?<br><br> 2ab<br> 4a^3b<br> 12ab<br> 72a^3b^2
Oksi-84 [34.3K]
12ab will be the right answer.

Since 24a^3 = 12ab(2a^2)

And 36ab^2 = 12ab(3b)
6 0
3 years ago
Read 2 more answers
4x - 4 - 8y + 8 - 5x + 1 =
SashulF [63]
-x-8y+5

Hope this helps, we have same name btw
3 0
3 years ago
Read 2 more answers
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
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